R - 5 1/6 = 10

r - 31/6 = 10
+ 31/6 +31/6

r = 91/6

So, r = 91/6.

And, I am not sure if the second one I am doing in right or wrong, but I am just guessing.
I think you use substitution method here.

8(x-2)+9 = 14
8x-16+9 = 14
8x-7 = 14
+7 +7
8x = 21
x = 21/8

So, the answer is 21/8

HOPE THID HELPS AND I REALLY HOPE THAT THE SECOND ANSWER IS RIGHT!!!!!!

3 0

3 years ago

I think of a number take away one and multiply the result by three but using x as your unknow

Georgia [21]

I think of a number, (55) = my x. -1 = 54 x 3 = 162.

4 0

3 years ago

Which of the following expressions is equivalent to y^-3?

Jet001 [13]

Answer:

the answer is 1/y^3

Step-by-step explanation:

when ever there is an negative exponent you flip it and put the base and exponent in a fraction under 1 hope this helps

7 0

3 years ago

As a result of medical examination, one of the tests revealed a serious illness in a person. This test has a high precision of 9

Elina [12.6K]

Answer:

0.0098

Step-by-step explanation:

Given,

Probability of test is positive if the person has disease, P(T/D)=0.99

Probability of test is negative if the person has disease,

P(T'/D) = 1-0.99 = 0.01

Probability of test is negative if the person hasn't disease, P(T'/D')= 0.99

Probability of test is positive if the person hasn't disease,

P(T/D') = 1 - 0.99 = 0.01

Probability of occurrence of disease, P(D) = 0.0001

Probability of not occurrence of disease,

P(D) = 1 - 0.0001 = 0.9999

Probability that test will be positive either disease is present or not,

P(T) = P(T/D).P(D)+P(T/D').P(D')

=0.99 x 0.0001 + 0.01 x 0.9999

= 0.000099 + 0.009999

= 0.010098

So, the probability that the person will have disease if the test is positive,

$P(D/T)\ =\ \dfrac{P(T/D).P(D)}{P(T)}$

$=\ \dfrac{0.99\times 0.0001}{0.010098}$

= 0.0098

So, the required probability will be 0.0098.

8 0

3 years ago