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Veseljchak [2.6K]
3 years ago
8

Write the equation for a line in standard form (Ax+By+C) that is perpendicular to y = 3x -

Mathematics
1 answer:
salantis [7]3 years ago
8 0

Answer:

x+3y-6=0

Step-by-step explanation:

given eqn is y=3x-2 which is 3x-y-2=0

the eqn of line perpendicular to given eqn is -x+3y+k=0

it passes through (6,4)

-6+3*4+k=0

or,. -6+12+k=0

or, k= -6

therefore, the eqn of line perpendicular to given eqn is x+3y-6=0

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One of the factors of the polynomial x3 + 5x2 + 6x is (x2 + 3x). What is the other factor?
butalik [34]

Answer:

x+2

Step-by-step explanation:

Dividing the poly by the known factor:

x3+5x2+6x    <u>| x2+3x</u>

-x3-3x2             x + 2  <- the answer is here

      2x2+6x

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To prove that, let's multiply the two factors and find the pylonomial back on:

(x2+3x).(x+2) = x3 + 2x2 + 3x2 + 6x = x3 + 5x2 + 6x

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