Answer:
meters
the meter is the largest unit of measurement of distance. If the meter is used, the bar chart would be more compact and the all the distances would be well represented on the bar chart
Step-by-step explanation:
6y-5=11
Move -5 to the other side. Sign changes from -5 to +5.
6y-5+5=11+5
6y=11+5
6y=16
Divide by 6 for both sides to get y by itself.
6y/6=16/6
Cross out 6 and 6, divide by 6 and then becomes 1*1*y=y
y=16/6
Reduce 16/6 by dividing by 2
16/2=8
6/2=3
Answer: y=8/3 or y=2 2/3
Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
dang
Step-by-step explanation:
A. x – 58 = 129
yes
B. x + 58 = 129
no
C. 180 – 129 − 59 = x
yes
D. 129 – 58 = xyes
E. (180 – 129) – 51 + x = 180no
hope this helps
