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Thepotemich [5.8K]
3 years ago
7

Find the correct equivalent fractions using multiplication

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:

\dfrac{25}{45}

Step-by-step explanation:

\dfrac{5}{9} \times \dfrac{5}{5} = \dfrac{5 \times 5}{9 \times 5} = \dfrac{25}{45}

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r-ruslan [8.4K]
Multiply and ull find ur answer
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Someone, please help me out here.
makvit [3.9K]

Answer:

Smallest to largest

Step-by-step explanation

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8 0
3 years ago
Need help with this asap………
Iteru [2.4K]

Answer:

y= 32

Step-by-step explanation:

HOPE THIS HELPS :)

8 0
2 years ago
Y^3-9y^2+y-9 I don't know how to solve this can you help
aleksley [76]
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9
3 0
3 years ago
Its a riddle I am a number between 60 and 100 my ones digit is 2 less then my tens digit i am a prime number
Mumz [18]
The answer is either 53 or 97.
7 0
3 years ago
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