Answer:
19
Step-by-step explanation:
9+10 is 19.
For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.
Answer:
<h2>
240.34</h2>
Step-by-step explanation:
ΔA = 90° - 31°
= 59°
sin A = perpendicular ÷ base
sin 59° = 400 ft ÷ y
1.6643 = 400 ft ÷ y
y = 400 ÷ 1.6643
y = 240.34 ft
<h2>
MARK ME AS BRAINLIST</h2>
Answer:
A. D
B. χ2 > 3.841
C. χ2 = 3.4806
D. 0.0621
Step-by-step explanation:
Question A: The hypotheses the dean should use are:
a) H0 : π1 - π2 ≥ 0 versus H1 : π1 - π2 < 0.
b) H0 : π1 - π2 ≤ 0 versus H1 : π1 - π2 > 0.
c) H0 : π1 - π2 ≠ 0 versus H1 : π1 - π2 = 0.
d) H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.
Answer: (d)
H0 : π1 - π2 = 0 versus H1 : π1 - π2 ≠ 0.
(B). Referring to the scenario above, the null hypothesis will be rejected if the test statistic is ________.
Answer: χ2 > 3.841
(C). Referring to the scenario above, the value of the test statistic is ________.
Answer: χ2 = 3.4806 (using the formula)
(D). Referring to the scenario above, the p-value of the test is ________.
Answer: 0.0621 (the answer could be looked up, in table)
