Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
To reduce a fraction divide the numerator and the denominator by their greatest common factor, GCF. ... The numerator and the denominator of the fraction are coprime numbers (no common prime factors, GCF = 1), the fraction cannot be reduced (simplified): irreducible fraction.
Answer:
First we have to find the value of x;
then we have to find the value of y;
Step-by-step explanation:
here,
2x= 12
x = 12\2
x = 6
now,
4y = 12
y = 12\4
y = 3
° the value of x is 6
° ° the value of y is 3
Answer:
5000
Step-by-step explanation:
Answer:
10:1
Step-by-step explanation:
as 6 kg = 6000g
so 6000g /600g
= 10 : 1. { 10 /1)