Answer:

Step-by-step explanation:
The coordinates of QS are:


The ratio is represented as:

Required
Find the coordinates of R
The coordinates of R is calculated by:

Substitute values for m, n, x's and y's



<em>None of the options is correct</em>
So, the first blank is for what kind of angle it is: acute, obtuse, reflex, straight, or right. The second blank is for what the measure of the angle is. You can find that out by looking at the protractor. It should tell you what the measure of the angle is. You can read the protractor by looking at the numbers. The numbers are the degrees of incline the angle measures, which is what you're looking for.
Answer:
No because 16+49 does not equal 121.
Step-by-step explanation:
first make 11 the hypotenuse and 4 and 7 side b and A
Use the pythagorean theorem: A^2+B^2=C^2
4^2+7^2=11^2
16+49=121
We have that
x²<span> + 7x + c
</span><span>Group
terms that contain the same variable
</span>(x² + 7x )+ c
<span>Complete
the square. Remember to balance the equation
</span>(x² + 7x+3.5² )+ c-3.5²
Rewrite as perfect squares
(x+3.5)²+ c-3.5²
so
c-3.5² must be zero
c-3.5²=0------- c=3.5²------> c=12.25
the answer isthe value of c must be 12.25