Recurrence functions are used to preedict the subsequent value in a sequence. The fourth term of the sequence based on the recurrence relation is 25
<h3>How to find the recurrence relation of a function?</h3>
Given the recurrence relations according to the question
s(1) = 2 and
s(2)=3
s(k) =s(k-1)+2s(k-2)+6
If s(1) = 2, hence;
s(3) =s(3-1)+2s(3-2)+6
s(3) = s2 + 2s1 + 6
s(3) = 3 + 2(2) + 6
s(3) = 13
Determine the fourth term:
s(4) =s(4-1)+2s(4-2)+6
s(4) = s3 + 2s2 + 6
s(4) = 13 + 2(3) + 6
s(4) = 25
Hence the fourth term of the sequence based on the recurrence relation is 25
Learn more on recurrence relation here: brainly.com/question/10636530
Answer:
Step-by-step explanation:
<u>Step 1: Pull a 7 from the top</u>
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<u>Step 2: Factor the bottom</u>
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<u>Step 3: Cancel the top (x+6) and the bottom (x+6)</u>
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Answer:
Answer:
My answer would be 9 unit away
Step-by-step explanation:
becuase you can subtract 0 from -9
0 + -9 would equal -9
then 9 - (-9) = 0
so 9 is my answer
sorry if i am wrong
