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oksano4ka [1.4K]
3 years ago
8

What are the missing operations?

Mathematics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

brainliest plzzzz

Step-by-step explanation:

48 _/_-8 = -6

-40 _/_ 8 = -5

12  _-_ (-2) = 14

18 _-_ (-12) = 6

18 _-_  (-20) = -2

22 _x_  (-0.5) = 11

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What is the acceleration of an object in air that has a velocity of Om/s?
pochemuha

Answer:

9.8m/s^2

Step-by-step explanation:

5 0
2 years ago
An aeroplane at an altitude of 200m observes the angle of depression of opposite points on the two banks of a river to be 45 and
blagie [28]

Answer:

  84.5 m

Step-by-step explanation:

It is often helpful to draw a diagram for word problems involving geometric relationships. One for this problem is shown below.

The mnemonic SOH CAH TOA reminds you of the relationship between sides of a right triangle:

  Tan = Opposite/Adjacent

Here we're given angles of depression measured from the horizontal (as shown in the diagram), but it is more convenient to use angles measured from the vertical. In particular, ∠BAO is the complement of 60°, and its tangent is the ratio OB/OA:

  tan(30°) = OB/OA

  OB = (200 m)·tan(30°) ≈ 115.47 m . . . . . . multiply by OA, use OA=200 m

Likewise, we have ...

  OC = (200 m)·tan(45°) = 200 m

Then the width of the river is the difference between these values:

  BC = OC -OB = 200 m - 115.47 m = 84.53 m

4 0
3 years ago
Someone please help me!!!!!
Katarina [22]

1. Answer (D). By the law of sines, we have \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} in any \triangle ABC.

2. Answer (C). The law of cosines, c^2=a^2+b^2-2ab\cos C,accepts up to three sides and an angle as an input.

3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.

4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of a^2 and 2ab\cos C are reversed.

5. Answer (B). By the law of sines, we have \frac{5}{\sin 40^\circ}=\frac{3}{\sin\theta}. Solving gives \theta\approx \boxed{23^\circ},157^\circ. Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!

6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.

6 0
3 years ago
Need help with this problem. ASAP
Mashutka [201]
Sorry I do not have added
7 0
3 years ago
Please help ASAP!!!!!!!!!!!
nexus9112 [7]
A is the answer because it doesn’t have a repeating x value
3 0
2 years ago
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