The probability is 0.3, or 30%.
These are not independent events; one pill being chosen will affect the probability after that, as the pill will not be replaced before selecting the next one.
The probability of getting exactly 1 narcotic pill is given by:
(6/15)(9/14)(8/13) = 432/2730. It does not matter what order the narcotic pill is in, the overall product will be the same.
The probability of getting exactly 2 narcotic pills is given by:
(6/15)(5/14)(9/13) = 270/2730. Again, the order these are found in does not matter, as it is multiplication and will not change the product.
The probability of all 3 pills being narcotics is given by:
(6/15)(5/14)(4/13) = 120/2730.
Adding these three possibilities together, we have 822/2730 = 0.30.
9.82 x 1/10 = 0.982
9.82 x 1/10 x 1/10 = 0.0982
9.82 x 1/10 x 1/10 x 1/10 = 0.00982
9.82 x 1/10 x 1/10 x 1/10 x 1/10 = 0.000982
Therefore:
9.82 x 10^(-4) = 0.000982
Answer:
71
Step-by-step explanation:
The question says we have 140 bags and we have 4 models
bags have buttons but no zips.
bags have zips but no buttons.
bags have neither zips nor buttons
bags have both zips and buttons
We don't know how many bags have zips and buttons but we know how many bags are produced. And other 3 types of bags number. So we can calculate
140-47-48-22=23
That means we have 23 bags that have zips and buttons
and
48 of the bags have zips too. that means we have 48+23=71 bags that have zips on them.
