Answer:
log[3(x+4)] is equal to log(3) + log(x + 4), which corresponds to choice number three.
Step-by-step explanation:
By the logarithm product rule, for two nonzero numbers 
and 
,
.
Keep in mind that a logarithm can be split into two only if the logarithm contains the product or quotient of two numbers.
For example, 
is the number in the logarithm ![\log{[3(x + 4)]}](https://tex.z-dn.net/?f=%5Clog%7B%5B3%28x%20%2B%204%29%5D%7D)
. Since is a product of the two numbers 
and 
, the logarithm can be split into two. By the logarithm product rule,
![\log{[3(x + 4)]} = \log{(3)} + \log{(x + 4)}](https://tex.z-dn.net/?f=%5Clog%7B%5B3%28x%20%2B%204%29%5D%7D%20%3D%20%5Clog%7B%283%29%7D%20%2B%20%5Clog%7B%28x%20%2B%204%29%7D)
.
However, 
cannot be split into two since the number inside of it is a sum rather than a product. Hence choice number three is the answer to this question.
Answer:
g(h(10)) = 43
Step-by-step explanation:
Given: g(x) = 4x – 4 and h(x) = 2x – 8.
We are to find g(h(10))
First we need to get g(h(x))
g(h(x)) = g(2x-8)
Replace x in g(x) with 2x-8 as shown:
g(2x-8) = 4(2x-8)-4
g(2x-8)= 8x-32-5
g(2x-8) = 8x-37
Hence g(h(x)) = 8x-37
g(h(10)) = 8(10)-37
g(h(10)) = 80-37
g(h(10)) = 43
Hence g(h(10)) is 43
Your answer is C
It's hard to describe I did it all in my head but please trust me that C is correct
