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Setler79 [48]
3 years ago
6

F(n)=5.(-2)n-1Complete the recursive formula of f(n).​

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

a(n) = (-2)(a_{n-1})

a_{1}=5

Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = a(r)^{n-1}

Where 'a' = First term of the sequence

r = common ratio

Recursive formula of a geometric sequence is,

a(n) = (a_{n-1}).(r)^{n-1}

a(n) = (-2)(a_{n-1})

Where, a_{1}=5

So the recursive formula will be a(n) = (-2)(a_{n-1})

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Answer:

9k^{3} -3k^{2}-29k-12

Step-by-step explanation:

Step 1: Expand by distributing sum groups.

3k(3k^{2} -5k-3)+4(3k^{2} -5k-3)

Step 2: Expand by distributing terms.

9k^{3} -15k^{2} -9k+4(3k^{2} -5k-3)

Step 3: Expand by distributing terms.

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Step 4: Collect like terms.

9k^{3}+(-15k^{2}  +12k^{2} )+(-9k-20k)-12

Step 5: Simplify.

9k^{3} -3k^{2}-29k-12

3 0
3 years ago
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Musya8 [376]

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Step-by-step explanation:

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AnnyKZ [126]

Answer:

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6 0
3 years ago
Read 2 more answers
-73 greater than or equal to 15 + 11x
Alecsey [184]
-73 ≥ 15 + 11x 
so the first thing you should do is to add -15 on both sides of the equation so you will have:
-73 -15 ≥ 11x 
- 88 ≥ 11x 
so the answer is:
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i hope this is helpful
have a nice day 
5 0
3 years ago
Read 2 more answers
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