Answer:
Yes
Step-by-step explanation:
Given,
Population mean Z = 600
Sample mean, µ = 586.50
Size of the sample, n = 10
Standard deviation, σ = 26.77
The testing hypothesis is,
Null hypothesis = µ<600
Alternative hypothesis = µ≥600
The test statistics is the calculated value of Z,
(Z- µ)/(σ/√n)
= (600-586.50)/(26.77/√10)
= (13.5*3.1623)/26.77
= 42.691/26.77
= 1.5947
And at 5% level of significance, the table value of Z = 1.644
Here, calculated Z<Table value of Z, so we accept the null hypothesis.
So, the null hypothesis is accepted. The mean value of the laptop is less than 600.
The rope is 1 and 1/3 long,1 is the same as saying 3/3,
this means that the rope is 3/3 + 1/3 long,so it is 4/3 foot long,
you now want to get half of this number so that each person has an equal length of rope,so multiply the length of rope by a half,
4/3 x 1/2 = 4/6 , which if simplified = 2/3, this means that each friend gets 2/3 foot of rope.
You can draw this in a diagram by drawing the 1 foot of rope, and then dividing it up into 3 sections. Then add the 1/3 foot of rope into the drawing. It should then be easy to see that altogether there are 4 separate sections of rope and that if each friend has two sections then they will be sharing equal amounts, so consequently each friend has two of the thirds of rope, 2/3
Answer:
interest
Step-by-step explanation:
you need to pay the bank interest because the bank needs to make money too, just like everyone
Answer:
a) H0: 
H1: 
b) 
And the critical values with 
on each tail are:
c) ![t=(10-1) [\frac{1.186}{1.34}]^2 =7.05](https://tex.z-dn.net/?f=%20t%3D%2810-1%29%20%5B%5Cfrac%7B1.186%7D%7B1.34%7D%5D%5E2%20%3D7.05)
d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Step-by-step explanation:
Information provided
n = 10 sample size
s= 1.186 the sample deviation
the value that we want to test
represent the p value for the test
t represent the statistic (chi square test)
significance level
Part a
On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:
H0:
H1:
The statistic is given by:
![t=(n-1) [\frac{s}{\sigma_o}]^2](https://tex.z-dn.net/?f=%20t%3D%28n-1%29%20%5B%5Cfrac%7Bs%7D%7B%5Csigma_o%7D%5D%5E2%20)
Part b
The degrees of freedom are given by:
And the critical values with on each tail are:
Part c
Replacing the info we got:
Part d
For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Answer:
detailed
Step-by-step explanation:
answer
