Answer:
public class print{
public static void fillArray(int[] arr, int initialValue){
int n = arr.length;
for(int i=0;i<n;i++){
arr[i] = initialValue++;
}
for(int i=0;i<n;i++){
System.out.print(arr[i]+" ");
}
}
public static void main(String []args){
int[] array = new int[5];
int initialValue =3;
fillArray(array,initialValue);
}
}
Explanation:
Create the function with two parameter first is array and second is integer.
Then, declare the variable and store the size of array.
Take the for and fill the array from the incremented value of initialValue by 1 at every run of loop.
After loop, print the element of the array.
Create the main function which is used for calling the function and also declare the array with size 5 and initialValue with 3. After that, call the function with this argument.
Pros:
-They can share information between different medical offices quicker than they could before hand.
-It is cheaper to send information via the internet than it is to hand it by hand
Cons:
-Hackers can get access to the medical patient's information.
-The upkeep costsof the internet connection may lower their income.
Answer:
b, with grace and maturity
Answer: Wired, Wi-fi, Wi-fi, A wired network, Wi-fi
Explanation:
Answer:
Check the explanation
Explanation:
Here is the program with function definition and two sample calls.
Code:
#include <iostream>
using namespace std;
//checkMe FUNCTION which takes values a, b and c
void checkMe(char &a, int &b, int &c)
{
//if sum of b and c is negative and a is 'n', b and c are set to 0, otherwise a is set to 'p'
if((b+c)<0 && a=='n')
{
b = 0;
c = 0;
}
else
{
a = 'p';
}
}
int main()
{
//first test case when else part is executed
char a = 'n';
int b = 5;
int c = 6;
checkMe(a, b, c);
cout<<a<<" "<<b<<" "<<c<<endl;
//second test case when if part is executed
a = 'n';
b = -4;
c = -5;
checkMe(a, b, c);
cout<<a<<" "<<b<<" "<<c<<endl;
return 0;
}
Kindly check the Output below:
