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DENIUS [597]
2 years ago
9

Help me please, I really need it​

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
6 0

Answer:

A OR C

Step-by-step explanation: I think it is A because in the question it says y=3

then y=ax²+b and on the A) it says a= -2 and b=2 OR the answer might be C) because it says ax² and a=<u>2 </u>

<u></u>

<u>im sorry if both of these are wrong and im sorry if you don't understand what i mean but i hope i helped you . :)</u>

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The equation of a circle is x^2 + y^2 -4x + 2y -11 =0 . What are the center and the radius of the circle? Show your work.
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Answer:

Center: (2,-1)

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Step-by-step explanation:

Equation of the circle in standard form is:

x^{2}+y^{2}+2gx+2fy+c=0

The radius of this circle is located at (-g, -f) and its radius is equal to:

r=\sqrt{g^{2}+f^{2}-c}

The given equation of circle is:

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Re-writing this equation in a form similar to the standard equation:

x^{2}+y^{2}+2(-2)x+2(1)y-11=0

Comparing this equation with standard equation we can say:

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And the radius will be = \sqrt{g^{2}+f^{2}-c} =\sqrt{(-2)^{2}+(1)^{2}-(-11)} =\sqrt{16} =4

Thus the radius of the given circle is 4 units.

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