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3 years ago

Please solve ASAP!!!!!!!!!

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

Answer:

C; D; B; B

Step-by-step explanation:

14) 1/((1/4) + (1/7)) = 1/(11/28) = 28/11 (C)

15) 1/((1/x) + (1/3x)) = 3--> (1/x) + (1/3x) = 1/3 --> 4/3x = 1/3 --> x = 4 (D)

16) 56 - 28 = 28 --> 28/(4*2) = 3.5 hours --> 56/3.5 = 16mph (when adding the stream's speed)--> 16mph - 4mph = 12mph (B)

17) 540 - 480 = 60 --> 60/(9*2) = 10/3 hours --> 540/(10/3) = 162 (when adding the current) --> 162mph - 9mph = 153mph (B)

Ulleksa [173]3 years ago

3 0

Answer:

14. A

15. C

16. B

17. B

Step-by-step explanation:

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3 years ago

Expand the given power using the Binomial Theorem. (10k – m)5

agasfer [191]

Answer:

$(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

$(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}$

∵ The binomial is $(10k-m)^{5}$

∴ a = 10k , b = -m and n = 5

∴ $(10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}$

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ $(10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})$

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3 years ago

Which of the following is true about the expression below?

agasfer [191]

Answer:

The first one

Explanation:

9 and 1/4 are both rational numbers (which are numbers that can be represented in a fraction; 9 can be represented as 9/1)
And since it equals to 9/4 (or 2 1/4) the product is also a rational number.

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