Answer: The three in the ten thousand place is 10 times the value of the three in the thousands place. And the three in the thousands place is 10 times smaller than the value of the three in the ten thousand place.
Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
Answer:
384, 216, 290, 192, 384
1446, 1 roll
Step-by-step explanation:
For rectangular boxes, calculate the sum of each side, then multiply it by two.
Box 1: 2(18 x 5) + 2(18 x 4) + 2(5 x 4) = 364
Box 3: 2(11 x 8) + 2(8 x 3) + 2(3 x 11) = 290
Box 5 is a cube (all sides equal), so you can find 1 side's area and multiply it by 6.
Box 5: 6(8 x 8) = 384
For triangular boxes, calculate the edges, then find the triangular area using area = 0.5(base x height).
Box 2: (15 x 3) + (9 x 3) + (12 x 3) + 2(0.5)(9 x 12) = 216
Box 4: 2(13 x 2) + (10 x 2) + 2(0.5)(10 x 12) = 192
Total: 364 + 290 + 384 + 216 + 192 = 1446
Rolls of wrapping paper:
Area of 1 roll = 30 x 60 = 1800
Since 1446 is less than 1800, you only need 1 roll of wrapping paper.
1 + 54 = 55
2 + 53 = 55
3 + 52 = 55
4 + 51 = 55
5 + 50 = 55
6 + 49 = 55
7 + 48 = 55
8 + 47 = 55
9 + 46 = 55
10 + 45 = 55
and so on...
I hope that helps. :)
So we need to cover 5.5% into a decimal.
0.055 = 5.5%
The house value is 120,000.
So
(1.055x) * (120,000)=
So
f(x)=1.055x * 120,000
