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ollegr [7]
3 years ago
8

How many rectangular arrays can Pablo make with all 36 tiles so none of the arrays show the same factor

Mathematics
1 answer:
anastassius [24]3 years ago
5 0
He can make 12 or 9 because 9x4=36 and 12x3=36
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Name the shaded angle in three different ways.​
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Triangle EFH

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What the volume of the soild
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A.264

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((8*6)/2)*11=264

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The time rate of change of a rabbit population PP is proportional to the square root of PP. At time t=0t=0 (months) the populati
frosja888 [35]

Answer:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

Step-by-step explanation:

For this case we cna use the proportional model given by:

\frac{dP}{dt} = k \sqrt{P}

Where k is a proportional constant, P the population and the represent the number of months

For this case we know the following initial condition P(0) =100 and P'(0) = 10

we can rewrite the differential equation like this:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

6 0
3 years ago
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