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Stels [109]
3 years ago
12

List the variables and constants in each expression. 3x+6

Mathematics
1 answer:
Iteru [2.4K]3 years ago
5 0
X is a variable
6 is a constant
3 is a coefficient
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Find the area of ABC.
love history [14]

Answer:

Suppose, a triangle ABC, whose sides are a, b and c, respectively. Thus, the area of a triangle can be given by; Area= 30

Area = 1/2 x 15 x4 = 30 square yards

Step-by-step explanation:

5 0
3 years ago
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Solve the equation. –x 8 3x = x – 6 x = –18 x = –14 x = 2 x = 4
LenKa [72]

The value of the variable x in the equation –x + 8 + 3x = x – 6 is - 14.

<h3>How to find variable in an equation?</h3>

The variables of an equation can be found as follows:

–x + 8 + 3x = x – 6

The variable in the equation is x.

Therefore,

–x + 8 + 3x = x – 6

combine like terms on the left side

-x + 3x + 8 = x - 6

2x + 8 = x - 6

subtract x form both sides of the equation

2x - x + 8 = - 6

x + 8 = -6

subtract 8 from both sides

x = -6 - 8

x = - 14

learn more on equation here: brainly.com/question/1347990

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3 0
2 years ago
Which is f(5) for the function –2x2 + 2x – 3?<br><br> –107<br> –63<br> –43<br> –37
Bess [88]

Answer:  C

Step-by-step explanation:

5 0
3 years ago
Solve the following equation for x.<br> 83x-1 = -73
musickatia [10]

Answer:

x=-72/83

Step-by-step explanation:

83x-1=-73

6 0
3 years ago
What is the product?
ZanzabumX [31]
To get the answer to this equation you first cancel out the 6! ;)

(x^2-1)(6x-1) / (x+1)

Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1

(x^2-1^2)(6x-1) / (x+1)

Then use the difference of squares!

(x+1)(x-1)(6x-1) / (x+1)

LASTLY cancel "x+1" !

so ur answer is (x-1) (6x-1)

That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)

YW!!!  ;) 
6 0
3 years ago
Read 2 more answers
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