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2 years ago

8v(v+3)(v+3) rewrite the expression factoring out (v+3)

Mathematics

1 answer:

kozerog [31]2 years ago

5 0

If we rewrite the expression 8v(v+3)(v+3) then we will get $v^{3}+6v^{2} +9v$

Given an expression 8v(v+3)(v+3).

We are required to rewrite the given expression.

Expression is a combination of numbers, symbols, fraction , determinants,indeterminants, coefficients. They are not mostly found in equal to form. It expresses a relationship of a line or something else.

The expression is 8v(v+3)(v+3). There are three terms in which variable is v.

To rewrite the expression we have to multiply all the three terms with each other which can be done as under:

=8v(v+3)(v+3)

= $(8v^{2}+24v)(v+3)$

= $8v^{3}+24v^{2}+24v^{2}+72v$

= $8v^{3}+48v^{2} +72v$

Now divide it by 8.

= $v^{3}+6v^{2} +9v$

Hence if we rewrite the expression 8v(v+3)(v+3) then we will get $v^{3}+6v^{2} +9v$ .

Learn more about expressions at brainly.com/question/723406

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