With the curve

parameterized by

with

, and given the vector field

the work done by

on a particle moving on along

is given by the line integral

where

The integral is then


Answer:
Dan is correct
Step-by-step explanation:
From the question, we have:

Required
The average
The average hour is calculated using:

So, we have:



<em>Dan calculated the mean as 3; while Bret calculated the mean as 4.</em>
<em>Hence, we can conclude that Dan s correct</em>
Answer:
faut-il faire les ponits avec le pallergrom de (−2 ; 3), (6 ; 2) (−1 ; 0) ?
Step-by-step explanation:
Answer:
-0.20
Step-by-step explanation:
Given the data:
Age at auction (x) ____price sold (y)
391
51
32
84
47
104
88
43
470
51
Y:
76.9
95.4
86.3
49.3
80
57
47.8
80
70
86.9
General formula for a simple linear regression :
y = ab + c
Where ;
y = predicted variable ; a = slope / gradient
b = predictor / independent variable ; c = intercept
From the result obtained from the calculator :
y = -0.01246X + 74.65552
Correlation Coefficient is used to measure the strength of relationship between linear variables.
The regression Coefficient obtained is - 0.20
This shows that there is a weak negative correlation between the age at auction and the price at which painting is sold. This is because the negative sign means that value of y decreases as x increases or vice versa, however, due to a correlation vale which is closer to 0 than 1 or - 1, we can conclude that the negative relationship between the variables is weak.
Answer:
1800
Step-by-step explanation:
15x12x10= 120x 15= 1800