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dexar [7]
3 years ago
12

When adding to integers with different signs, how do you find the sign?

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

the largest number would be the sign that that number has

Step-by-step explanation:

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I need help on this
valentinak56 [21]

Answer:

Im pretty sure it's the 2nd one

8 0
3 years ago
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If f is a function that f(f(x)) = 2x² + 1, which is the value of f(f(f(f(3)))? Please help!
Sloan [31]

f(f(3))=2\cdot3^2+1=19\\f(f(f(f(3))))=2\cdot19^2+1=723

5 0
3 years ago
Increments of seven ​
BaLLatris [955]

Answer:

Specific Learning Outcomes:  

Solve problems that involve finding powers of a number

Description of mathematics:  

In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.  

Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further,  these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …

The same is true of the digit in the tens place.

6 0
3 years ago
1. Ada purchased a house using a fixed rate mortgage. The annual interest rate is 6.3%
vlabodo [156]

The monthly  payment on the mortgage is option C) $2537.44

<u>Step-by-step explanation</u>:

  • Principal (P): $ 295,000
  • Rate (r): 6.3%  = 0.063
  • Number of times compounded (n): 12months\times15 years = 180
  • Number of years = 15

The formula is A = P(1 + r/n)^nt

⇒ A = 295000(1+0.063/180)^(180\times15)

⇒ A = 295000(180.063/180)^2700

⇒ A = 295000 (1.00035)^2700

⇒ A = 758854.5

Interest = Amount - Principle

⇒ 758854.5 - 295000

⇒ Interest = 463854.5

∴ The monthly payment for 15 years = 463854.5 / (15\times12)

The monthly  payment on the mortgage = 2576.9 (approximately option C)

8 0
3 years ago
On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did thei
finlep [7]
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day. 
6 0
3 years ago
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