Answer:
Im pretty sure it's the 2nd one
Answer:
Specific Learning Outcomes:
Solve problems that involve finding powers of a number
Description of mathematics:
In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.
Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further, these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …
The same is true of the digit in the tens place.
The monthly payment on the mortgage is option C) $2537.44
<u>Step-by-step explanation</u>:
- Principal (P): $
295,000
- Rate (r): 6.3% = 0.063
- Number of times compounded (n): 12months
15 years = 180
- Number of years = 15
The formula is A = P(1 + r/n)^nt
⇒ A = 295000(1+0.063/180)^(180
15)
⇒ A = 295000(180.063/180)^2700
⇒ A = 295000 (1.00035)^2700
⇒ A = 758854.5
Interest = Amount - Principle
⇒ 758854.5 - 295000
⇒ Interest = 463854.5
∴ The monthly payment for 15 years = 463854.5 / (15
12)
The monthly payment on the mortgage = 2576.9 (approximately option C)
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.