The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
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Answer:
Clockwise rotation 90 ° about origin
R_{90, clockwise, origin}(x,y) -> (y,-x)
J(-4,1) therefore
R_{90, clockwise, origin}J(-4,1) -> J'(1,+4) this answer was form other person credits to him/her
Step-by-step explanation:
Answer:
The domain of g(x) is the same as the domain of the parent function.
The range is the same as the range of the parent function.
The function g(x) increases over the same x-values as the parent function.
The function g(x) decreases over the same x-values as the parent function.
Answer:
whats the question
Step-by-step explanation:
