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alexandr1967 [171]
2 years ago
10

Number sequence for OTTFFSS?​

Mathematics
1 answer:
Elanso [62]2 years ago
5 0

Answer:

  1234567

Step-by-step explanation:

One

Two

Three

Four

Five

Six

Seven

One possible number sequence is 1, 2, 3, 4, 5, 6, 7.

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Use the distributive property to simplify the following expression: -3(-x - 3y)
alexandr402 [8]

Step-by-step explanation:

-3(-x -3y) = 3( x +3y) = 3x+9y

7 0
3 years ago
On Halloween 4 friends each received 4⁄5 of a pound of candy. How much candy did they receive total?
Leokris [45]

Answer:

16/5 or 3 1/5

Step-by-step explanation:

Your equation would be 4/5*4 which equals 16/5

4 0
3 years ago
Help me please!!! And thank you!!!!
katen-ka-za [31]
<h2>Answer:</h2>

The last answer - 9x squared y squared

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8 0
2 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
HELP ASAP!!!!!!!!!!!!!
creativ13 [48]

Answer:

$36

Step-by-step explanation:

20x.80=16

20+16=36

Hence, the original price is $36

8 0
2 years ago
Read 2 more answers
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