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Alexxx [7]
3 years ago
10

Pick one its math

Mathematics
1 answer:
True [87]3 years ago
8 0
INITIAL VALUE HOPEFULLY IM SO SORRY IF ITS WRONG
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Solve the inequality<br> -1/3h ≥ 7<br> A. h ≥ –21<br> B. h ≤ 7 1/3<br> C. h ≤ –21<br> D. h ≥ -2 1/3
JulsSmile [24]
The Answer Is C Fam...................
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Counting how many errors are in one chapter of a book is an example of measuring what kind of quality characteristics
AnnZ [28]

Answer: Attributes.

Step-by-step explanation:

An attribute is characterized as a person, position, or thing's quality or characteristic. Individuals in real life and fictional characters have different characteristics. Someone could be called attractive, charming, funny, or intelligent, for instance. Well, in math, an attribute is a characteristic of a math object - it's what this object has. An attribute of the book is the number of errors in a chapter of the book.

8 0
3 years ago
If the geometric mean of a and 34 is 6 sqrt(17) find the value of a
Alborosie

Using the geometric mean concept, it is found that the value of a is 18.

----------------------

The geometric mean, of a data-set of n elements, (n_1, n_2, ..., n_n), is given by:

G = \sqrt[n]{n_1 \times n_2 \times ... \times n_n}

That is, the nth root of the multiplication of all elements.

----------------------

In this question:

  • Two elements(n = 2), a and 34.
  • G = 6\sqrt{17}

Thus:

\sqrt{34a} = 6\sqrt{17}

We find the square of each side, so:

(\sqrt{34a})^2 = (6\sqrt{17})^2

34a = 36\times17

Simplifying both sides by 17:

2a = 36

a = \frac{36}{2}

a = 18

The value of a is 18.

A similar example is given at brainly.com/question/15010240

3 0
3 years ago
Given sin theta= 6/11 and sec theta &lt; 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

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3 years ago
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Anestetic [448]
Do 51×5 and you will get the answer 255
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