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3 years ago

23. Tell whether the sequence is arithmetic. If it is, what is the common difference? (1

Mathematics

1 answer:

Airida [17]3 years ago

4 0

Answer: O Yes; 6

Yes it is Arithmetic; the difference is 6

Step-by-step explanation:

If the numbers keep changing by the same value being added or subtracted, it is Arithmetic.

-15 - (-9) = -6 -9 - (-3) = -6 -3 - 3 = -6

"Same difference" as the saying goes!

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Find the value of X, then find AB and DC.

zhannawk [14.2K]

Answer:

X=2, AB=14, DC=14

Step-by-step explanation:

3x+8=x+12

Subtract x from both sides

2x+8=12

Subtract 8 from both sides

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Divide by 2 on the sides

Answer: x=2

Then replace the x's with (2) and multiply

3(2)+8 and (2)+12

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3 years ago

Which data set is represented by the modified box plot?

IgorLugansk [536]

Answer:A

Step-by-step explanation: A has everthing correct the median is between the numbers 92 98 making it 95 these are the numbers is order 79,86,88,88,92,98,100,106,115,136

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HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---<em>Approximated</em>

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