Answer:
a) 0.0167
b) 0
c) 5.948
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.16 ounces
Standard Deviation, σ = 0.08 ounces
We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.
Formula:
a) Standard deviation of 23 bags

b) P( fill volume of 23 bags is below 5.95 ounces)
P(x < 5.95)
Calculation the value from standard normal z table, we have,
c) P( fill volume of 23 bags is below 6 ounces) = 0.001
P(x < 6) = 0.001
Calculation the value from standard normal z table, we have,


If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.
Answer:
Part A:
-Minimum: 10
-Q1: 17.5
-Median: 30
-Q3: 42.5
-Maximum: 50
Step-by-step explanation:
Part B: IQR= 25
This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.
Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.
Answer:
5x-2y
Step-by-step explanation: u multiply
There is no graph doe ...