Answer:
259.274 kW
Explanation:
Given:
Area of the lava, A = 1.00 m²
Temperature of the surrounding, T₁ = 30.0° C = 303 k
Temperature of the lava, T₂ = 1190° C = 1463 K
emissivity, e = 1
Now,
from the Stefan-Boltzmann law of radiation the rate of heat loss is given as,
u = σeA(T₂⁴ - T₁⁴)
where,
u = rate of heat loss
σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m²∙K⁴
on substituting the respective values, we get
u = 5.67 × 10⁻⁸ × 1 × 1 × (1463⁴ - 303⁴)
or
u = 259274.957 W
or
u = 259.274 kW
Remain the same
Explanation:
If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.
Work done is the force applied to move a body through a distance.
Work done = F x d
where F is the applied force
d is the distance moved
Now;
if:
f = 2f
d = 
d
Input the parameter:
Work done = fxd = 2f x d = fd
The work done will still remain the same
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A D and E are all types of light
During the internal examination, the pathologist drains the intestines, removes any undigested food and feces, and examines the contents of the stomach. This examination could give the pathologist clues of the time of death, and the location of death. The process of digesting and defecation vary from person to person, the entire process is generally considered to take approximately 40 hours in adults
