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elena55 [62]
3 years ago
13

Before there was central heating, hot water bottles were used to keep people warm at night. These flat containers were filled wi

th hot water and placed at the foot of the bed, under the blankets. How was the heat energy transferred from the hot water bottle into the space under the blankets?
Physics
1 answer:
mestny [16]3 years ago
8 0
The answer is D radiation because the heat from the hot water bottle is radiating the space around the hot water bottle. Hope this helps
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Air is composed primarly of which of the following gases?
romanna [79]
Nitrogen and carbon dioxide
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3 years ago
in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of th
Nata [24]

Answer:

R = 73.25 m

Explanation:

We have,

Initial speed of the ball is 27 m/s

It is projected at an angle of 40 degrees

The maximum range of the ball is given by :

R=\dfrac{u^2\sin2\theta}{g}

Plugging all the values we get :

R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m

So, the maximum range of the ball is 73.25 m

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3 years ago
What is 28 degrees Celsius converted to Fahrenheit?
torisob [31]
28 degrees celsius converts to 82.4 degrees in Fahrenheit :) 
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3 years ago
Read 2 more answers
You are moving a wagon with a friend's help you push on the left side of the wagon with 25 of force while your friend pulls from
Pavel [41]

Answer:

10N to the left side towards you

Explanation:

The net force is the resultant force that acts on a body.

Force is a push or pull on a body.    

 Push to left side  = 25N

 Pull to the right  = 15N

Net force  = Push to left side   -  Pull to the right  = 25N  - 15N

 Net force  = 10N to the left side towards you

The net force is therefore 10N to the left side towards you

5 0
3 years ago
A 100 kg box as showsn above is being pulled along the x axis by a student. the box slides across a rough surface, and its posit
Anit [1.1K]

Answer:

a) 2 m/s

b) i) K.E = 50 (1.5t^2 + 2) ^2\\

ii) F = 3tm

Explanation:

The function for distance is x = 0.5t ^3 + 2t

We know that:

Velocity = v= \frac{d}{dt} x

Acceleration = a= \frac{d}{dt}v

To find speed at time t = 0, we derivate the distance function:

x = 0.5 t^3 + 2t\\v= x' = 1.5t^2 + 2

Substitute t = 0 in velocity function:

v = 1.5t^2 + 2\\v(0) = 1.5 (0) + 2\\v(0) = 2

Velocity at t = 0 will be 2 m/s.

To find the function for Kinetic Energy of the box at any time, t.

Kinetic \ Energy = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times 100 \times (1.5t^2 + 2) ^2\\\\K.E = 50 (1.5t^2 + 2) ^2\\

We know that Force = mass \times acceleration

a = v'(t) = 1.5t^2 + 2\\a = 3t

F = m \times a\\F= m \times 3t\\F = 3tm

6 0
3 years ago
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