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Fofino [41]
3 years ago
15

9. The temperature at noon was 84° F and it began to drop 0.8° each hour. If the current temperature is 79.2° F, write and solve

an equation to determine the number of hours that have passed.
Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:6 hours have passed by.

Step-by-step explanation:

0.8x= 84-79.2 where x is the number of hours.

O.8x = 4.8

Divide both sides by 0.8

X= 6

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Which of the following numbers is a multiple of 6?
LiRa [457]
<span>The multiples of 6. Answer : 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,1</span>
4 0
3 years ago
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Siri am I a mix of recipe that calls for 1 1/2 cups of flour and 3/4 to get butter Jeremiah uses three sticks of butter how many
Inga [223]

Answer:

6 cups

Step-by-step explanation:

jeremiah 4× the recipe

3/4×4=3

so 1 1/2×4=6

8 0
3 years ago
ur a HS photographer taking pictures fir 2 classes of 21 students each. on average, each individual pic takes 3 minutes and a cl
goblinko [34]
2 classes of 21 students each
21 × 2 classes = 42 students in total
42 × 3 mins = 126 minutes for 42 students
10 mins for 2 class pics = 20 minutes
126 + 20 = 146 minutes = 2 hours and 26 minutes

It should take 146 minutes (2 hours and 26 minutes) to take all the pictures.
6 0
3 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
Can somebody explain how to do this question
evablogger [386]

Answer:

The answer is D

Step-by-step explanation:

Remember:

Contrapositive means that if you reverse the hypothesis and the conclusion the statement will mean the same thing

7 0
3 years ago
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