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Liula [17]
3 years ago
15

Jessie read 1/3 of a book in the morning, and she read some more at night. By the end of the day, she still had 1/5 of the book

left to read. How much of the book did Jessie read at night?
Mathematics
2 answers:
Mrac [35]3 years ago
6 0
7/15 She read 7/15 at night
PilotLPTM [1.2K]3 years ago
5 0

Answer:

7/15

Step-by-step explanation:

I converted 1/3 into 5/15

Then I converted 1/5 into 3/15

I added 5/15 and 3/15 and got 8/15

Then I subtracted 15/15-8/15=7/15.

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Write 37 and 2/3% as a fraction in simplest form.<br> URGENT
Tems11 [23]

Answer:

101 2/3

Step-by-step explanation:

8 0
2 years ago
Please answer the six questions in the picture please
lisov135 [29]
Y=mx+b
m=slope
b=y itnercept
remember the points go in (x,y) form
also, an easy way to find points is to subsitute values for x andn get values for y

so
6. y=5x-1
 some points are (0,-1) (1,4) (2,9) (314)

7. y=-x+8
some points are (0,8) (1,7) (2,6) (3,5)

8. y=0.2x+.3
somepoints are (0,0.3) (1,0.5) (2,0.7) (3,0.9)

9. y=1.5x-3
somepoints are (0,-3) (1,-1.5) (2,0) (3,1.5)

10. y=-1/2x+4
somepoints are (0,4) (1,7/2) (2,3) (3,5/2)

11. y=2/3x-5
some points are (0,-5) (1,-13/3) (2,-11/3) (3,-3)
6 0
3 years ago
Read 2 more answers
Mindy has $10.75 to buy school supplies. She spends $3.96 at one store for a package of glue sticks, but she still needs to buy
maks197457 [2]
She can only spend $2.62
5 0
3 years ago
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Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
3 years ago
Part 1: Add: 3 3/8 + 7 3/4<br> Part 2: Subtract: 12 3/8 - 8 1/5
Yuliya22 [10]
Part one is 11 1/8.
part two is 4 7/40.
4 0
3 years ago
Read 2 more answers
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