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maria [59]
3 years ago
14

Will mark as brainliest if correct

Mathematics
1 answer:
Nataly_w [17]3 years ago
6 0

Answer:

X = 2?

Step-by-step explanation:

Have a great day

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ASAP Point A, located at (-3, -3) is translated 6 units up, resulting in the location of point A'. What other transformation wou
miss Akunina [59]

Answer:

(3,3)

Step-by-step explanation:

A reflection of this across the y-axis is (-3,3). A reflection of Point A, (-3,-3), over the x-axis is also (-3,3).

3 0
3 years ago
Please help i really need help
lukranit [14]

9514 1404 393

Answer:

  17/99

Step-by-step explanation:

Replace the digits 23 in your example with the digits 17 and you have your answer:

  0.\overline{17}=\dfrac{17}{99}

_____

In general, a 2-digit repeat will have 99 as its denominator. If the digits are a multiple of 3 or 11, then the fraction can be reduced. 17 is prime, so the fraction cannot be reduced.

3 0
3 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
3 years ago
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