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Answer:
a) 15/8 b) 25/18
Step-by-step explanation:
a) First bring all the fractions to a common denominator (I'm going to use 8th's). 5/8 is already simplified, 1/2=4/8, and 3/4=6/8. Then, simply add the numerators and leave the denominator:
Since this can not be simplified any further, your final answer is 15/8.
b) Start by bringing all the fractions to a common denominator (for this problem, we'll use 18th's). 2/3=12/18, 1/6=3/18, and 5/9=10/18. Then just add all the numerators and leave the denominator the same:
Since this cannot be simplified further either, your final answer is 25/18.
Hope this helps! :)
Answer:
The approximate p-value for the suitable test
<em>0.05 < p < 0.1</em>
|t| = |-1.5806| = 1.5806
t = 1.5806 < 2.009 at 0.05 level of significance
<em>Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.</em>
<u>Step-by-step explanation</u>:
<u><em>Step(i)</em></u>:-
Given mean of the Population 'μ' = 120 milligrams
Given random sample size 'n' = 50
Given mean of the sample x⁻ = 116.2 milligrams
Standard deviation of the sample 'S' = 17 milligrams
Null hypothesis : 'μ' = 120
Alternative hypothesis : 'μ' < 120
<u><em>Step(ii):</em></u>-
<em>Test statistic </em>
<em>Degrees of freedom</em>
<em>ν = n-1 = 50 -1 =49</em>
t₀.₀₅ = 2.009
|t| = |-1.5806| = 1.5806
t = 1.5806 < 2.009 at 0.05 level of significance
<em>Null hypothesis is accepted</em>
<em>Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.</em>
<u><em>P- value:-</em></u>
<em>The test statistic |t| = 1.5806 at 49 degrees of freedom</em>
<em>The test statistic value is lies between 0.05 to 0.1</em>
<em>0.05 < p < 0.1</em>
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