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const2013 [10]
3 years ago
15

What's the answer? please

Mathematics
1 answer:
Aliun [14]3 years ago
3 0
Let's see


so you have to add the bottom numbers and the top numbers then add the whole numbers so it's 23 15\28
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The cost of petrol is 60 rupees per litre a petrol bunk sells 750
Crank

Answer:

45000rupees

Step-by-step explanation:

cost of 1 litre of petrol=60rupees

cost of 750 litres of petrol=750×60rupees

=45000rupees

6 0
3 years ago
The volume of cone A is equal to the volume of cylinder B. In addition, their radii are
tekilochka [14]

Answer:

3:1

Step-by-step explanation:

A cone has the same volume formula as a cylinder, except it is 1/3 as much. So to have the same volume, a cone would need to be 3 times as tall.

5 0
2 years ago
THIS IS DUE TOMORROW HELPPPP
bogdanovich [222]

Answer:

Answers are below

Step-by-step explanation:

1. For every 4 boys, there are 3 girls.

2a. 14-p

2b. (d+f)/8

2c. 2x+5

2d. c/6

3a. 2a+2b

3b. 21d+12e

3c. 8a+24b

4. Speed = distance/time

5a. 101 boys and 121 girls

5b. 8 won + 4 lost = 12 games in total

6a. 65

6b. 657

6c. 98

7a. 49.99

7b. 110.92

Hope these answers are correct! Please mark me as brainliest!

3 0
3 years ago
Five soccer players each contributed an equal share toward a $50 gift for their coach. Write and solve an algebraic equation to
shtirl [24]
5x = 50
Where x represents the (equal) amount of money each player contributed
As you can see, you can easily solve the equation above to get:
x = 10
Each player contributed $10 toward a $50 gift.
5 0
4 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
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