Solve for c :
x⁴ + cx² + 100 = 0
cx² = -(x⁴ + 100)
c = - (x⁴ + 100)/x²
If x = 0, the right side is undefined and c would have no solution.
Let the first number be = x
Then the second number = 2x
The third number = 2x - 5
Their sum = 55
This can be written in an equation as =
x + 2x + 2x - 5 = 55
= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )
= x + 2x + 2x = 60
= 5x = 60
= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )
= x = 12
The first number = x = 12
The second number = 2x = 2 × 20 = 24
The third number = 2x - 5 = 24 - 5 = 19
Therefore , the three numbers are 12 , 24 and 19 .
Answer:
y = 3/4 + 7
Step-by-step explanation:
you must put the equation into the form of y = mx + b
add 6x to both sides and put it in front of the 56
8y = 6x + 56
y must be by itself by x does not so we divide everything by 8
y = 6/8x + 7
we must simplify the fraction 6/8
y = 3/4x + 7
Answer:
x/23
Step-by-step explanation:
The bag of money can be represented by x
Adam is 1 person.
1 + 22 = 23
x is divided by 23
x/23
~ Zoe
