Answer:
1. G.P.E = 24 J
2. center of mass
Explanation:
Given the following data;
Mass = 2kg
Height, h = 1.2m
Acceleration due to gravity = 9.8 N/kg or m/s².
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;

Where;
- G.P.E represents potential energy measured in Joules.
- m represents the mass of an object.
- g represents acceleration due to gravity measured in meters per seconds square.
- h represents the height measured in meters.
Substituting into the formula, we have;

G.P.E = 23.52 to 2 S.F = 24 Joules.
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.
Answer:
E
Explanation:
Using Coulomb's law equation
Force of the charge = k qQ /d²
and E = F/ q
substitute for F
E = ( K Qq/ d² ) / q
q cancel q
E = KQ / d²
so twice the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²
Answer:Cross-pollination is two plants that work together to pollinate and self-pollinate is when a flower pollinates itself. ... Why do you think plants surround the seeds with a yummy fruit? To protect the seeds so that they can reproduce. How is cross-pollination different from self-pollination?
Explanation:
Answer and Explanation:
1. Evaluate the function x(t) at t=0.5

2. The period of motion T can be calculated as:

Where:

So:

3. The angular frequency can be expressed as:

Solving for k:

4. Find the derivate of x(t):

Now, the sine function reach its maximum value at π/2 so:

Solving for t:

Evaluating v(t) for 0.6603981634:

So the maximum speed of the block is:
In the negative direction of x-axis
5. The force is given by:

The cosine function reach its maximum value at 2π so:

Solving for t:

Evaluating x(t) for 3.016592654:

Therefore the the maximum force on the block is:
