Answer:
-0.105 m/s
Explanation:
Given that
Mass of the astronaut, m(a) = 68.5 kg
Mass of the tool, m(t) = 2.25 kg
Speed of the tool after it is thrown, v(t) = 3.20 m/s
We know that momentum of a particle,
p = mv
See the attachment for calculations
Therefore, the speed is 0.105 m/s and it moves in the opposite direction.
This acceleration is directed towards the center of thecircle<span>. ... So for an object moving in a </span>circle<span>, there must be an inward </span>force<span> acting upon it in order to</span>cause<span> its inward acceleration. This is sometimes referred to as the </span>centripetal force<span> requirement.</span>
Answer:
λ_A = 700 nm
, m_B = m_a 2
Explanation:
The expression that describes the diffraction phenomenon is
a sin θ = m λ
where a is the width of the slit, lam the wavelength and m an integer that writes the order of diffraction
a) They tell us that now lal_ A m = 1
a sin θ = λ_A
coincidentally_be m = 2
a sin θ = m λ_b
as the two match we can match
λ _A = 2 λ _B
λ_A = 2 350 nm
λ_A = 700 nm
b)
For lam_B
a sin λ_A = m_B λ_B
For lam_A
a sin θ_A = m_ λ_ A
to match they must have the same angle, so we can equal
m_B λ_B = m_A λ_A
m_B = m_A λ_A / λ_B
m_b = m_a 700/350
m_B = m_a 2
That depends on a number of things that we don't know because you haven't told us.
If any of the things on this list changes, then the answer to the question changes:
-- What is "it" ?
-- Was it dropped, thrown, fired, or launched ?
-- From what height above the ground ?
-- With what speed ?
-- In what direction ?
-- What is the acceleration of gravity where this took place ?
-- Did any drag act on it, due to liquid or gas, before it hit the ground ?
