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asambeis [7]
3 years ago
8

What is the distance an object travels and the direction of its motion from starting point?

Physics
1 answer:
castortr0y [4]3 years ago
6 0

Answer: Well you didn't give any answers so my guess would be it depends how much force you put into it and where you throw it.

Explanation:

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A single frictionless roller-coaster car of mass m = 750. kg tops the first hill with speed v = 15.0 m/s at height h = 20.0 m as
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In which of the following situations is the Doppler effect absent?
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The source and the observer are moving towards each other. The observer is moving toward the source. The source is moving away from the observer
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A toaster draws 8 A of current with a voltage of 120 V. Which is the power used by the toaster?
dexar [7]
U=120 \text{ V}\\
I=8\text{ A}\\
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7 0
3 years ago
Please help.. I'm desperate.
rosijanka [135]

Answer:

Newton's Second Law tells us that the more mass an object has, the more force is needed to move it. A larger rocket will need stronger forces (eg. more fuel) to make it accelerate. The space shuttles required seven pounds of fuel for every pound of payload they carry.

Explanation:

7 0
3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
hodyreva [135]

Answer : The correct option is, (c) 3.7\times 10^2J/^oC

Explanation :

First we have to calculate the energy or heat.

Formula used :

E=V\times I\times t

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

E=(3.6V)\times (2.6A)\times (350s)

E=3276J

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}

where,

C = heat capacity of the calorimeter

T_{initial} = initial temperature = 20.3^oC

T_{final} = final temperature = 29.1^oC

Now put all the given values in this formula, we get:

C=\frac{3276J}{(29.1-20.3)^oC}

C=372.27J/^oC=3.7\times 10^2J/^oC

Therefore, the heat capacity of the calorimeter is, 3.7\times 10^2J/^oC

7 0
3 years ago
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