Question

For a standard normal distribution, find the approximate value of P(-0.78 sz51 16). Use the portion of the standard normal

Answer 1

Answer:

The value of P (-0.78 < z < 1.16) is 0.6593.

Step-by-step explanation:

A random variable $Z=\frac{X-\,u}{\sigma}$ is said to follow a standard normal distribution if $X\sim N(\mu,\ \sigma^{2})$. The random variable Z has mean 0 and variance 1.

The probability expression is:

P (-0.78 < z < 1.16)

Use the standard normal table to compute the probability value as follows:

$P (-0.78$

                              $=P(z$

Thus, the value of P (-0.78 < z < 1.16) is 0.6593.