Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
<h2>
<em>Answer</em></h2>
<em>361</em><em>π</em><em>km²</em>
<h2>
<em>Explanation</em></h2>
• the formula to find the area of a circle is A=πr²
<h3> =>
<em>A=π(19km)²</em></h3><h3>
<em>A=π(19km)² => A=361πkm</em>²</h3><h2>
<em>I</em><em> hope</em><em> it</em><em> helps</em><em>!</em><em>!</em></h2>
4 X 13 thats all you have to do mark me as brainliest if you could
Answer:
The graph is shifted 1 unit right
The graph is shifted 2 units down
Step-by-step explanation:
We are given
Parent function as

New function as

we can also write as

We can see that
1 is subtracted to x-value
and 2 is added to y-value
So, f(x) is shifted right by 1 unit
and
f(x) is shifted up by 2 unit