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4 years ago

A____ function is a function that can be expressed as the quotient of two polynomial functions

Mathematics

2 answers:

r-ruslan [8.4K]4 years ago

7 0

Answer:

rational function

Step-by-step explanation:

That would be a "rational function;" it's the "ratio" of two polynomial functions, with the understanding that the denominator may not be zero.

r-ruslan [8.4K]4 years ago

6 0

Answer:

Rational expression

Step-by-step explanation:

A rational expression is a quotient of two polynomials, where the polynomial in the denominator is not zero. Rational expressions can often be simplified by removing terms that can be factored out of the numerator and denominator. These can be either numbers or functions of x

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If I get $154 and they increase it by 5% how much have they increased

vampirchik [111]

Answer:

154×5×100=770×100=77000

8 0

3 years ago

Read 2 more answers

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

Paraphin [41]

Answer:

Step-by-step explanation:

For a quadratic equation ax² +bx +c= 0, the quadratic formula is as below:

$\boxed{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }$

x² -12x +7= 0

$x = \frac{ - ( - 12)± \sqrt{( - 12) {}^{2} - 4(1)(7) } }{2(1)}$

$x = \frac{12± \sqrt{144 - 28} }{2}$

$x = \frac{12± \sqrt{116} }{2}$

$x = \frac{12± \sqrt{4(29)} }{2}$

$x = \frac{12±( \sqrt{4})( \sqrt{29} )}{2}$

$x = \frac{12±2 \sqrt{29} }{2}$

$x = 6± \sqrt{29}$

$∴x = 6 + \sqrt{29} \: \: \: or \: \: \:x = 6 - \sqrt{29}$

6 0

3 years ago

The range for the given domain of the function is .

pav-90 [236]

The domain of a function is the numbers on the x coordinate that the function can be. The range is the same, but for the y axis. So for the function you gave, if the domain is all numbers between -1 and 3, you plug in those numbers.

3 0

3 years ago

F(x) = -3x-3 g(x) =2x^3+2<br> Find f(6) and g(-3)

wlad13 [49]

Answer:

$f(6)=-21\\\\g(-3)=-52$

Step-by-step explanation:

When given the following two functions,

$f(x) =-3x-3\\g(x)=2x^3+2$

One is asked to evaluate the functions for, (f(6)) and (g(-3)). One can do this by substituting the values (6) into the function (f) and (-3) into the function (g). These values will replace the parameter (x).

$f(6)=-3(6)-3\\$