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3 years ago

10

Find two positive numbers whose product is 36 and whose sum is a minimum.

1 answer:

alukav5142 [94]3 years ago

8 0

Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2

The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.

If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
So the 2 numbers are 18 and 18 and the maximum product is 324,

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Step-by-step explanation:

In the geometric series:

$a_1=4\\ \\r=\dfrac{1}{2}$

The nth term of the geometric sequence can be calculated using formula

$a_n=a_1\cdot r^{n-1}$

In your case, n = 10, then

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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By the power rule,

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(this seems to be the step you're not getting?)

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