Answer:
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Step-by-step explanation:
The function that could model this periodic phenomenon will be of the form

The tide varies between 3ft and 9ft, which means its amplitude
is

and its midline
is
.
Furthermore, since at
the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is
.
The period of the full cycle is 14 hours, which means


giving us

With all of the values of the variables in place, the function modeling the situation now becomes

Simplifying
3a + 2b + c = 26
Solving
3a + 2b + c = 26
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-2b' to each side of the equation.
3a + 2b + -2b + c = 26 + -2b
Combine like terms: 2b + -2b = 0
3a + 0 + c = 26 + -2b
3a + c = 26 + -2b
Add '-1c' to each side of the equation.
3a + c + -1c = 26 + -2b + -1c
Combine like terms: c + -1c = 0
3a + 0 = 26 + -2b + -1c
3a = 26 + -2b + -1c
Divide each side by '3'.
a = 8.666666667 + -0.6666666667b + -0.3333333333c
Simplifying
a = 8.666666667 + -0.6666666667b + -0.3333333333c
JK = MN because of Given
∠JLK = ∠MLN because of the vertical angle theorem
JL = LN because of definition of midpoint
ΔJLK = MLN because of SAS
∠K = ∠N because corresponding angles of congruent triangles are congruent.
Hope this helps!<span />
Answer 144 ft2
Step-by-step explanation: