Answer:
40
Step-by-step explanation:
We know there are 16 oz in a pound
We can use ratios
15 x
----- = ----------
6 oz 16 oz
Using cross products
15 * 16 = 6x
240 = 6x
divide by 6
240/6 = 6x/6
40 =x
Question:
Find the constant of proportionality k. Then write an equation for the relationship between x and y

Answer:
(a) 
(b) 
Step-by-step explanation:
Given

Solving (a): The constant of proportionality:
Pick any two corresponding x and y values


The constant of proportionality k is:




Solving (b): The equation
In (a), we have:

k can also be expressed as:

Substitute values for x1, y1 and k

Cross multiply:

Open bracket

Add 10 to both sides


Yo I’m just here so I can ask my question!
Answer explaining=
This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y.
We are told that X + Y = 59
We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59 [then combine like terms]
9+5Y=59 [subtract 9 from both sides]
5Y=50 [divide both sides by 5 to isolate the Y]
Y=10 [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
84!
All the sides are 18,24, and 30. Then the two triangles are 12.