In this problem all the necessary informations are provided. Total capacity of the tank is given as 2560 gallons. It is also given that after 2 weeks or 14 days , only 1944 gallons of water is left. The number of days the whole tank will be empty is required to be found.
Let us assume that the number of days required to empty the tank = x
Then
Now amount of water consumed in 14 days = 2560 - 1944
= 616 gallons
So
616 gallons of water used in = 14 days
2560 gallons of water will be used in = (14/616) * 2560
= 58.18
Then the whole tank will last approximately 58 days if calculated to the nearest whole number.
Answer:
3/2 and -4
Step-by-step explanation:
that is the answer
1/2 of 14 is 7. multiply 14/1 to 1/2.
<h3>
Answer: G) -2</h3>
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Explanation:
I'm assuming you meant to say (a+y)^2 + 2y
Replace each copy of 'a' with 5. Replace each copy of 'y' with -3. Use PEMDAS to simplify.
(a+y)^2 + 2y
(5 + (-3))^2 + 2(-3)
(5-3)^2 + 2(-3)
(2)^2 + 2(-3)
4 + 2(-3)
4 - 6
-2
So (a+y)^2 + 2y = -2 when a = 5 and y = -3.
