First option is correct.
Since we have given that
JKL is a right triangle.
Length of JK = 12
Length of KL = 5
By Pythagoras theorem, we get that
So, cos (L) would be
cos(L)=base/hypotenuse
cos(L)=5/13
Hence, First option is correct.
learn more about Pythagoras theorem and cosine ratios here:
brainly.com/question/9027282
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)
<span>tanx = 3/10 </span>
<span>x=16.7 B </span>
<span>2) </span>
<span>tan 64 = 173/x </span>
<span>x = 84.38 D </span>
<span>3) </span>
<span>tan21 = x/442 </span>
<span>x= 169.67 B </span>
<span>4) </span>
<span>tanx = 16.2/48.3 </span>
<span>x = 18.54 A </span>
<span>5) </span>
<span>tanx = 8/6.5 </span>
<span>x = 50.91 C </span>
<span>6) </span>
<span>tan89 = 1149/x </span>
<span>x=20.06 A </span>
<span>7) </span>
<span>tanx = 21/12 </span>
<span>x= 60.26 B </span>
<span>8) B </span>
<span>9) </span>
<span>tanx = 25/63 </span>
<span>x = 21.64 C </span>
<span>10) </span>
<span>tanx = 60/15 </span>
<span>x= 75.96 D</span>
Answer:
9* 3 ^ (x-2)
Step-by-step explanation:
g(x) = 3^x
We know a^ (b) * a^(c) = a^ (b+c)
9* 3 ^ (x+2) = 3^2 * 3 ^(x+2) = 3^(2+x+2) = 3^x+4 not equal to 3^x
3*(9^(x+2)) = 3*3^2(x+2) = 3^1 * 3^(2x+4) =3^(2x+4+1) = 3^(2x+5) not equal
9* 3 ^ (x-2) = 3^2 * 3 ^(x-2) = 3^(2+x-2) = 3^x equal to 3^x
3*(9^(x-2)) = 3*3^2(x-2) = 3^1 * 3^(2x-4) =3^(2x-4+1) = 3^(2x-3) not equal
Answer:
The probability of falling into a type I error, when testing a hypothesis test, consists of:
Probability of rejecting the null hypothesis when, in reality, this hypothesis is true.
Probability of rejecting the null hypothesis when, in reality, this hypothesis is true, is:
Probability of Affirm that Chemistry exam will NOT cover only chapters four and five, since the Chemistry exam will cover only chapters four and five.
That is, alpha is the probability that Carmin decides to study additional chapters, unnecessarily.
Step-by-step explanation:
