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2 years ago

A line's y-intercept is 5, and its slope is 1. what is its equation in slope intercept form?

Mathematics

1 answer:

kotegsom [21]2 years ago

5 0

Answer:

y = x+5

Step-by-step explanation:

The slope intercept form of an equation is

y = mx+b where m is the slope and b is the y intercept

y = 1x + 5

y = x+5

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Nat2105 [25]

Answer:

After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46

Step-by-step explanation:

We need to complete the square:

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x^2 -2(x)(2)+(2)^2 -8 -4 =0

(x^2 -4x +4) - 12 = 0

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(x-2)^2 -12 =0

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taking square root on both sides

$\sqrt{(x-2)^2}= \sqrt{12} \\(x-2) = \pm\sqrt{12} \\x = \pm\sqrt{12} +2\\x = \sqrt{12}+2 \,\,and\,\,x=-\sqrt{12}+2\\x= 3.46+2 \,\,and\,\,x=-3.46+2\\x =5.46\,\,and\,\,x=-1.46$

So, After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46

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3 years ago

Find the slope of the line. please help will mark brainlyest

Mamont248 [21]

Answer:

m = 1

Step-by-step explanation:

slope = (y₂-y₁)/(x₂-x₁)

m = (4 - -1) / 1 - -4) = 5/5 = 1

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2 years ago

A line's y-intercept is 5, and its slope is 1. what is its equation in slope intercept form?​

A line's y-intercept is 5, and its slope is 1. what is its equation in slope intercept form?