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USPshnik [31]
3 years ago
8

PLEASE HELP ME: ASAP

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Ok so

Corresponding sides and angles are a pair of matching angles or sides that are in the same spot in two different shapes.

It would basically be a ratio (7:14)

My best help would be this

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. This proves that the ratio of areas of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.

I really hope this helps, dont have a lot of time today to answer a lot of questions so have a great day and lmk if this helps!

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7 0
3 years ago
What is the ratio of the afternoon to morning temperatures shown in the table?
Monica [59]
I would help you but you need to post the table with the question..
6 0
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Graph the slope-intercept equation y=Mx+b<br> y= -3x - 6
lbvjy [14]
I currently don’t have any paper on me to graph it for you, but I am able to give you coordinates.

Explanation:

When given an equation in the form y=Mx+b, we can immediately get the x-intercept and y-intercept.

To get the x intercept:
Make y=0

0=-3x-6
-2=x

So your coordinates are (-2;0)

To get the y intercept:
It is the b value

y=-6

So your coordinates are (0;-6)

Plot those on your graph and draw a line through them, write the equation next to the line and put an arrow on either end of the line.

Hope this helps! Feel free to comment for any questions you may have.
7 0
3 years ago
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A semicircle is attached to the side of a rectangle as shown.
Genrish500 [490]

Answer:

58.8\ mm^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a rectangle plus the area of semicircle

Step 1

Find the area of the rectangle

The area of the rectangle is equal to

A=bh

we have

b=9\ mm

h=3\ mm

substitute

A=9*3=27\ mm^{2}

Step 2

Find the area of semicircle

The area of semicircle is equal to

A=\frac{1}{2}\pi r^{2}

we have

r=9/2=4.5\ m

substitute

A=\frac{1}{2}(3.14)(4.5^{2})=31.8\ mm^{2}

Step 3

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27\ mm^{2}+31.8\ mm^{2}=58.8\ mm^{2}


6 0
3 years ago
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

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(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
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