Once the first team is defined, so is the other one. With no loss of generality, we can define the first team as the one with one (1) woman. There are 3 ways to have 1 woman on the team.
The remaining 3 team members are men. There are C(5,3) = 10 ways to choose 3 men from 5. Thus, the first team can be formed in 3×10 = 30 different ways.
There are 30 ways to form the teams as described.
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The function C(n, k) or nCk (choose k from a pool of n) is defined as
... nCk = n!/(k!(n-k)!)
so 5C3 = 5!/(3!(5-3)!) = 5·4/2 = 10
- Total section=8
- Total odd={1,3,5,7}
- |E|=4
Theoretical probability of getting odd no
Now
Experimental probability
P(E)=6/10=3/5
So
Compare both
Experimental probability is greater than. theoretical probability
The answer to this is C. Although the initial ratio of Grade 7 to Grade 8 students is 17:34, which is 1:2, and which can be represented well by the 6 sides of the cube by putting 1 and 2 as Grade 7 and 3-6 as Grade 8, the problem with the cube rolls is that the probabilities will not change after students are chosen. The problem states that students cannot be selected more than once, so the cube roll will only work the first time, and may not be accurate for subsequent rolls.
Your answer would be y=3 1/2 ,y=3.5