In the statement regarding outlier we have to fill "most" to complete the statement.
Given An outlier is a data value that is numerically distant from_________ of the other data points in a set of data.
We have to fill the blank. We can fill " most" in the blank.
If a number in data is more than 1.5 times the length of the box away from either of the upper and lower quartile of the distribution then that number is said to be an outlier.
There are two types of outliers: upper outliers, lower.
If any values in the data set are greater than the upper boundary then those values are the upper outliers.
If any values in the data set are less than the lower boundary then those values are called lower outliers.
Lower quartile =
Upper quartile=
Hence we have to use most in the sentence to complete it.
Learn more about outliers at brainly.com/question/3631910
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Step-by-step explanation:It says:
There are 3 strawberry yoghurts, 2 peach yoghurts and 4 cherry yoghurts in a fridge.
Kate takes a yoghurt at random from the fridge.
She eats the yoghurt.
She then takes a second yoghurt at random from the fridge.
Work out the probability that both yoghurts were the same flavour.
PRT+PRT=Total Interest
0.03x+0.11(2x)=104.5
0.25x=104.5
x=418
x+2x, 418+2(418)=1254
Total Investment=1254 dollars
<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em>
Answer:
Sample size minimum is 60
Step-by-step explanation:
given that you want to create a 99% confidence interval with a margin of error of .5.
The population standard deviation is equal to 1.5
i.e. 
Confidence level = 99%
Since population std deviation is known, we can use Z critical value for finding margin of error
Z critical value for 99% = 2.58
Margin of error = 
Equate this to 0.5 and solve for n
