Question

A bird (B) is spotted flying 6,000 feet from a tower (T)). An observer (O) spots the top of the tower (T) at a distance of 9,000 feet. What is the angle of depression from the bird (B) to the observer (O)? Right triangle OTB is shown. Side OT labeled 9000 and side TB is labeled 9000. The angle B is labeled x degrees.

Answer 1

Answer:

The angle will be "48.7°".

Step-by-step explanation:

In ΔTBO, the given values are:

TB = 6,000 feet

BO = 9,000 feet

Now,

To find the angle,

⇒  $Cos \ B =\frac{TB}{BO}$

On putting the estimated values, we get

⇒   $Cos \ x=\frac{6000}{9000}$

⇒   $Cos \ x=0.66$

⇒          $x=Cos^{-1} \ 0.66$

⇒          $x=48.7^{\circ}$    

Answer 2

Answer:

56.31

Step-by-step explanation:

9000/6000 (opposite/adjacent)=1.5

$tan^{-1}$(1.5)=56.30993247

Round the answer to 56.31