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Rzqust [24]
3 years ago
14

What is the value of x? x + 3 = - 9 Enter your answer in the box.

Mathematics
2 answers:
kow [346]3 years ago
3 0

Move +3 to the right side of the equal sign (which becomes -3) in order to combine the numbers to find x:

x=-9-3

-9-3 is -12

x=-12

Stels [109]3 years ago
3 0

x + 3 = -9    <em>subtract 3 from both sides</em>

x + 3 - 3 = -9 - 3

<h3>x = -12</h3>
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What are the steps for this question?
padilas [110]

Answer:

1. Add 5 to both sides

2. Divide both sides by 2

3. Take the square root of both sides

4. Subtract 2 from both sides

Step-by-step explanation:

2(x+2)²-5=93

<em>Add 5 to both sides</em>

2(x+2)²=98

<em>Divide both sides by 2</em>

(x+2)²=49

<em>Square root both sides</em>

x+2=7

<em>Subtract 2 from both sides</em>

x=5

7 0
4 years ago
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Helena wants to find the perimeter of the graphed quadrilateral ABCD.
gizmo_the_mogwai [7]
Side cd will do the trick

5 0
4 years ago
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If 0 &lt; z ≤ 90 and sin(9z − 1) = cos(6z + 1), what is the value of z? z = 3 z = 4 z = 5 z = 6
iogann1982 [59]

Answer:

z = 6

Step-by-step explanation:

sin (9z - 1) = cos (6z + 1)

90 - (9z - 1) = 6z + 1

90 - 9z + 1 = 6z + 1

9z + 6z = 90

15z = 90

z = 6

I Hope I've helped you.

7 0
3 years ago
Can someone plz help with this question idk how to do it im stooopid
V125BC [204]

Answer: 96 square units (choice B)

==============================================

Explanation:

Triangle OBI has a base of OI = 12 units along the horizontal component, and CB = 8 is the vertical component or the height.

area of triangle OBI = 0.5*base*height

area of triangle OBI = 0.5*12*8

area of triangle OBI = 48 square units

--------------------------------------

Now find the area of the trapezoid GNIO. The two horizontal components are the parallel bases GN = 4 and OI = 12. The height of this trapezoid is the vertical component CD = 6, where point D is added on to be at location (0,-6) on the graph.

area of trapezoid = (height*(base1+base2))/2

area of trapezoid GNIO = 6*(4+12)/2

area of trapezoid GNIO = 48

Coincidentally, the triangle and trapezoid both have the same area

--------------------------------------

The last thing to do is add the two areas of the triangle and trapezoid

total area = (area of triangle OBI) + (area of trapezoid GNIO)

total area = (48) + (48)

total area = 96 square units

8 0
3 years ago
If h(2)=7 and h'(2)=-2,find d/dx [(h(x))/(x)] <br> A. –11/4 B. 2 C. D. 8 E. 16
valentinak56 [21]

Answer:

A. \frac{-11}{4}

Remember that if f and g are functions with g(x)\neq 0 then, \frac{d}{dx}\frac{f(x)}{g(x)}=\frac{f'(x)g(x)-g'(x)f(x)}{g(x)^2}.

Then,

\frac{d}{dx}\frac{h(x)}{x}=\frac{h'(x)x-h(x)}{x^2}

Evaluating in x=2,

\frac{h'(2)*2-h(2)}{2^2}=\frac{-4-7}{4}=\frac{-11}{4}

Then the answer is A.

7 0
3 years ago
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