Question

PLEASE HELP ME with an explanation. Thanks in advance

Answer 1

Answer:

3) 0.30

The probability a randomly selected student plays a sport given they work part time = 0.30

Step-by-step explanation:

Step(i):-

Given  'A' plays a sport

          B work part time

Given P(A) = 0.48

         P(B)  = 0.40

        P(A∩B) =0.12

       P(A∪B)¹ =0.24

Step(ii):-

By using conditional probability

$P(B/A) = \frac{P(BnA}{P(A)}$

and similarly $P(A/B) = \frac{P(AnB}{P(B)}$

The probability a randomly selected student plays a sport given they work part time

Now $P(A/B) = \frac{P(AnB}{P(B)}$

       $P(A/B) = \frac{0.12}{0.40}= 0.30$

Final answer:-

The probability a randomly selected student plays a sport given they work part time = 0.30