Answer:
y = 2*x^2 - 2*x - 24
Step-by-step explanation:
If we have a quadratic function with roots a and b, we can write the equation for that function as:
y = f(x) = A*(x - a)*(x - b)
Where A is the leading coefficient.
In this case, we know that the roots are: 4 and -3
Then the function will be something like:
f(x) = A*(x - 4)*(x - (-3) )
f(x) = A*(x - 4)*(x + 3)
Now we need to determine the value of A.
We also know that the graph of the function passes through the point (3, -12)
This means that:
f(3) = -12
Then:
-12 = A*(3 - 4)*(3 + 3)
-12 = A*(-1)*(6)
-12 = A*(-6)
-12/-6 = A
2 = A
Then the equation is:
y = f(x) = 2*(x - 4)*(x + 3)
Now we need to write this in standard form, so we just need to expand the equation:
y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)
y = f(x) = 2*(x^2 - x - 12)
y = f(x) = 2*x^2 - 2*x - 24
Then the relation is:
y = 2*x^2 - 2*x - 24
Answer:
c expression and b is number
Step-by-step explanation:
Step-by-step explanation:
x'=53
σ=16
n=144
a) hypothesis
H0:µ=55
Ha:µ<55
This is a left tailed test
b) Test statistics
- z=(x'-u)/(sigma/sqrt {n})
=(53-55)/(16/sqrt{144})
=-1.5
c)Pvalue at z=|-1.5|
pvalue= p(z>1.5)
=1-0.933193
=0.066807
=0.0668
<u>Decision</u>
since pvalue>alpha(0.05) fail to reject the null hypotheis.
<u>Conclusion</u>
There is not sufficient evidence to support the claim the new computer program has not reduce the time to retrieve the data.
d)since Pvalue>alpha(0.025),so fail to reject the null hypothesis.
No, change in conclusion.
(x+6)2+(y-10)2=36 , would be your equation.
